1 0 0
1 1 -1
-1 0 1
Solución: AA' =
1 0 0
3 1 -2
-2 0 -1
(AA', E) = 1
1 0 0 1 0 0
3 1 -2 0 1 0
-2 0 -1 0 0 1
r2-3r1, r2 2r1
1 0 0 1 0 0
0 1 -2 -3 1 0
0 0 -1 2 0 1
p>
R3 *(1), r2 2r3
1 0 0 1 0 0
0 1 0 -7 1 -2
0 0 1 -2 0 -1
Entonces (aa')-1 =
1 0 0
-7 1 -2
-2 0 -1
Si está satisfecho, adopte.