f(2)=-4+2ln2=aln2-4b①
F'(2)=a/2 -4b=-3②, y a=2, b=1.
(2)Supongamos f (x) = f (x)-g (x) = 2lnx-2x 2+2x, f '(x)= 2-4x+2/x =-2( x-1)(2x+1)/x.
haga que F '(x)> 0, luego 0
(3) Sea G(x)= f(x)+m = 2 lnx-2x ^ 2 +m , G '(x)= 2/x-2x = 2(1-x ^ 2)/x, entonces G(x) está en (1. 0①, G(e)< 0②, G(1) >0③ , 2