Preguntas y respuestas del examen de química analítica de la provincia de Heilongjiang

pH=8.00

Coeficiente de partición S2

=[S2-]/{ [H2S] [HS-] [S2-]}

= ka 1 * ka2 /{[h ]^2 [h ]* ka 1 ka 1 * ka2 }

=(1.3*10^-7 *7.1*10^-15) /{ (10^-8.00) ^2 (10^-8,00)*(1,3*10^-7) (1,3*10^-7 *7,1*10^-15)}

=6,6*10^-7

Coeficiente de partición de Ag

=[Ag ]/{[Ag ] [Ag(NH3) ] [Ag(NH3)2 ]}

= 1/{ 1 β1 *[NH3] β2*[nh3]^2}

=1/ {1 10^3.24 *0.01 10^7.05 *(0.01)^2}

=8.8* 10^-4

Ag2S lt= = gt2Ag S2-

2s s

[Ag ]=2s *8.8*10^-4

[S2-]= *6.6*10^-7 Sur

ksp(ag2s)=[ag ]^2 *[S2-]=(2s *8.8*10^-4)^ 2 *(s *6,6*10^-7)=2,0*10^-49

s=4,6*10^-13 mol/L