f(x)=[(1-cosx) sinx]/sinx=[1-1 2(sin(x/2))^2 2sin(x/2)cos(x/2) ]/2sin(x/2)cos(x/2)]=1 tan(x/2)
T=π/(1/2)=2π Su intervalo monótono es (2kπ-π. , 2kπ π), k∈Z
f(x)=[(1-cosx) sinx]/sinx=[1-1 2(sin(x/2))^2 2sin(x/2)cos(x/2) ]/2sin(x/2)cos(x/2)]=1 tan(x/2)
T=π/(1/2)=2π Su intervalo monótono es (2kπ-π. , 2kπ π), k∈Z