=2(3a-2b)^2 2(2a 3b)^2
=2(9a^2-12ab 4b^2) 2(4a^2 9b^2 12ab)
=18a^2 8a^2 8b^2 18b^2
=26a^2 26b^2
Según: (a-b) 2 = (b-a) 2
2. Fórmula original = {[A-(1/2)]*[A (1/2)]2 *[A 2 (1/4)]2 p >
=[a^2-(1/4)]^2*[a^2 (1/4)]^2
={[a^2-(1/4) ) ]*[a^2 (1/4)]}^2
=a^8-(1/8)a^4 (1/256)
3. Fórmula original=(5/3)[(-3/4)x 6y 3 (6/5)x 3y 4-(9/10)xy 5]÷xy 3.
=[(-5/4)x^6y^3 2x^3y^4-(3/2)xy^3]/xy^3
=(-5 /4)x^5 2x^2y-(3/2)y^2
4. Cuando x= -3, existe:
4=a(-3). ^5 b(-3)^3 c(-3)-2
Es decir: -[A * 3 5 B * 3 3 C * 3 2] = 4, entonces: A * 3 5 B * 3 3 C * 3 =-6.
Cuando x=3, y = a * 3 5 b * 3 3 c * 3-2 =-6-2 =-8.