S△COD = (DO/BO)×S△BCO = 12k = S△ABO
Área total s△PBC = 4+12+12k×2 = 16+24k.
△PAB∽△PBC
S△PAB=kS△PBC=16k+24k?
S△ADO=kS△BCO=12k
12k+16k+24k? =4
24k? +28k-4=0
6k? +7k-1=0
Δ=7?+4×6=49+24=73
k=[-7+√73]/12
S△PBC=16+24k
=16+2[-7+√73]
=2+2√73
S△COD = (DO/BO)×S△BCO = 12k = S△ABO
Área total s△PBC = 4+12+12k×2 = 16+24k.
△PAB∽△PBC
S△PAB=kS△PBC=16k+24k?
S△ADO=kS△BCO=12k
12k+16k+24k? =4
24k? +28k-4=0
6k? +7k-1=0
Δ=7?+4×6=49+24=73
k=[-7+√73]/12
S△PBC=16+24k
=16+2[-7+√73]
=2+2√73