∴Fórmula original = 3 ∫ (0, 1) dx ∫ (0, 1)ln[(y+1)/(x+1)]dy. y, ∫ (0, 1)ln[(y+1)/(x+1)]dy = 2ln 2-1-ln(1+x),
∴Fórmula original = 3 ∫ ( 0,1)[2ln 2-1-ln(1+x)]dx = 0.
Para referencia.
∴Fórmula original = 3 ∫ (0, 1) dx ∫ (0, 1)ln[(y+1)/(x+1)]dy. y, ∫ (0, 1)ln[(y+1)/(x+1)]dy = 2ln 2-1-ln(1+x),
∴Fórmula original = 3 ∫ ( 0,1)[2ln 2-1-ln(1+x)]dx = 0.
Para referencia.